WebMar 14, 2024 · 要解决这个问题,你可以尝试以下方法之一: 1. 将 if_sheet_exists 参数设置为 'replace',这样如果工作表已经存在,它会被替换为新的工作表。 2. 将 if_sheet_exists 参数设置为 'new',这样如果工作表已经存在,它会创建一个新的带有数字后缀的工作表名称,例如 Sheet1_1。 3. 先检查文件中是否已经存在同名的工作表,如果存在则删除或重 … WebApr 10, 2024 · But the code fails x_test and x_train with cannot reshape array of size # into shape # ie. for x_train I get the following error: cannot reshape array of size …
ValueError: cannot reshape array of size 1 into shape (1,43)
Web6. You can reshape the numpy matrix arrays such that before (a x b x c..n) = after (a x b x c..n). i.e the total elements in the matrix should be same as before, In your case, you can … WebAug 13, 2024 · Then it applies the transpose axes to the image and, also the new shape for the array is calculated using the axes variable. I'm having an issue in reshaping the transposed array with the new_arr_shape. As I keep getting the error being unable to reshape the array of size 276800 into shape (1,1,1). maltose and sucrose
cannot reshape array of size 1 into shape (48,48)
Web1 Answer Sorted by: 1 you want array of 300 into 100,100,3. it cannot be because (100*100*3)=30000 and 30000 not equal to 300 you can only reshape if output shape … WebOct 4, 2024 · 1 Answer Sorted by: 2 You need 2734 × 132 × 126 × 1 = 45, 471, 888 values in order to reshape into that tensor. Since you have 136, 415, 664 values, the reshaping is impossible. If your fourth dimension is 4, then the reshape will be possible. Share Improve this answer Follow answered Oct 4, 2024 at 15:30 Dave 3,744 1 7 22 Add a comment … WebMar 17, 2024 · import numpy as np n = 10160 #n = 10083 X = np.arange (n).reshape (1,-1) np.shape (X) X = X.reshape ( [X.shape [0], X.shape [1],1]) X_train_1 = X [:,0:10080,:] X_train_2 = X [:,10080:10160,:].reshape (1,80) np.shape (X_train_2) If you cannot make sure that X is 10160 long I suggest one of the following solutions: maltose benedict\u0027s test results